someone plzzzz answer exam starting in a today evening
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Answer:
sin^3x+cos^3x/sinx+cosx+sinx×cosx
=a^3+b^3=(a+b)(a^2+b^2-ab)
=(sinx+cosx)(sin^2x+cos^2x-sinx×cosx)/sinx+cosx+sinx×cosx
=(sin^2x+cos^2x-sinx×cosx)+sinx×cosx
=(1-sinx×cosx)+sinx×cosx
=1-sinx×cosx+sinx×cosx
=1 ans.
I hope this help u
chakri200610:
if possible can u please write on a paper and send photo
still in 7th
hard to understand
though helps
thank you
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