Math, asked by msbrar004pggll0, 1 year ago

someone plzzzzz solve this
its humble request

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Answers

Answered by super92
0
i think the answer is (x +2) (a^2 + b^2 + c^2)
Answered by nk10
3
x+a^2+2b^2/b+c +x^2+b^2+2c^2/c+a +x+c^2+2a^2/a+b=0
Or, (x+a^2+2b^2/b+c) -(b-c) +(x+b^2+2c^2/c+a)-(c-a) +(x+c^2+2a^2/a+b)-(a+b)=0
Or, x+a^2+2b^2-b^2+c^2/b+c +x+b^2+2c^2-c^2+a^2/c+a +x+c^2+2a^2-a^2+b^2/a+b=0
Or, (x+a^2+b^2+c^2)/b+c +(x+a^2+b^2+c^2)/c+a +(x+a^2+b^2+c^2)/a+b=0
Or, (x+a^2+b^2+c^2)(1/b+c +1/c+a+1/a+b)=0
Or, x+a^2+b^2+c^2=0(since 1/b+c+1/c+a+1/a+b not equal to 0)
Or, x= -(a^2+b^2+c^2)

msbrar004pggll0: Thankyou very much
super92: welcome my dear
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