Question

Someone push an object on the floor with force of 350 N. The floor exerts a
friction force 70 N. Determine the work done by force to move the object as
far as 6 meters.

Answer 1

Answer :

To Find :-

The Work done by the body to move the object.

Given :-

• Force Acting = 350 N

• Frictional Force = 70 N

• Distance in the direction of force = 6 m

We know :-

$\underline{\boxed{\bf{Work\:Done = Force \times Displacement}}}$

Concept :-

According to the Question , a opposite force i.e, Friction is acting on the body.

So, first we have to find the total force acting on the object.

After finding the total force , we can use the formula for work done and substitute the values in it to find the work done !!

Solution :-

⠀⠀⠀⠀⠀⠀⠀Total force on the object :-

Let the total force be $F_{t}$

Thus ,to Find the total force we need to find the some of the two opposite forces Acting on the body.

$:\implies \bf{F_{t} = 350 + (- 70)} \\ \\ :\implies \bf{F_{t} = 350 - 70} \\ \\ :\implies \bf{F_{t} = 280 N} \\ \\ \therefore \bf{Total\:Force = 280 N}$

Hence , the total force acting on the object is 280 N.

⠀⠀⠀⠀⠀⠀Work done by the body :-

Using the formula and substituting the values in it, we get :-

⠀⠀⠀⠀⠀⠀⠀⠀⠀$\bigstar$ The unit of Work ⠀⠀⠀⠀⠀⠀⠀⠀⠀ done is Joule !!.

$:\implies \bf{Work\:Done = Force \times Displacement} \\ \\ \\ :\implies \bf{W = 280 \times 6} \\ \\ \\ :\implies \bf{W = 1680} \\ \\ \\ \therefore \purple{\bf{Work\:Done = 1680 J}}$

Hence, the work done by the body is 1680 J.