Someone's car will not start, so a friend helps him by pushing it. By pushing as hard as he can for 10 seconds, be makes the car reach a speed of 2ms⁻¹. Calculate the acceleration he has given to the car
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Answer:
Someone's car will not start, so a friend helps him by pushing it. By pushing as hard as he can for 10 seconds, be makes the car reach a speed of 2ms⁻¹. Calculate the acceleration he has given to the car
- The car is at rest .
- therefore its initial velocity is 0
- Time given here is 10 seconds
- Final velocity of the car is 2ms⁻¹.
- acceleration of the car = ?
From 1st equation of motion ,
- v = 2 (v means final velocity)
- u = 0 ( u mean initial velocity )
- a = ? ( a mean acceleration)
- t = 10 s ( t means time )
v = u + at
➡️ 2 = 0 + a × 10
➡️ 2 = 0 + 10a
➡️ 2 - 0 = 10a
➡️ 2 = 10a
➡️ 2/10 = a
➡️ a = 0.2 ms²
Therefore , acceleration = 0.2ms²
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2) साखळी पूर्ण करा :
ब
अ
क
। विस्तीर्ण क्षेत्रावरील ज्वालामुखीय उद्रेक १) विभाग -V
१) I ते XII
अंदमान आणि निकोबार बेटे
२) भेगीय उद्रेक
२) गट पर्वत
मर्केली प्रमाण
३) तीव्रता
३) अति उच्च भूकंपीय संवेदनशीलता
मंद हालचाली
४) विभंग
४) घनरुप
फिलिपाईन्स
५) ज्वालामुखीय बॉम्ब ५) डेक्कन ट्रॅप
ज्वालामुखीय पदार्थ
६) पॅसिफिकचे अग्निकंकण ६) मॅयॉन
चूक सहसंचय ओळखा:
इ) A आणि R हे दोन्ही बरोबर आहे आणि R RA
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