Question

someone solve the b of 3 plz plz plz..urgent​

Answer 1

Answer:

∠ABD is an exterior angle of ∆DBC

∠ABD = ∠BCD + ∠BDC ..( remote interior angle theorem)

= 89° + 27°

= 116°

∠ABD = ∠ABE ......(B-E-D)

In ∆ ABE

∠ABE + ∠BAE + ∠AEB = 180° ( sum of measures of angles of the triangle is 180°)

22°+116°+∠AEB = 180°

138° + ∠AEB = 180°

∠AEB = 42°

∠AEB + ∠AED = 180 (angles in linear pair)

42° + c =180°

c = 180°-42°

c = 138°