Question

Someone tell me answer for this​

Answer 1

a.) From serial no. 3, we come to know that both object distance and image distance are equal. This is possible in a conversation lens only if it is placed at 2f1. Therefore 2f1 is 30. Therefore, f=15cm.

b.)Serial no. 6 ain't right as an object placed between O and f1 is always real and has to be -ve.

c.)scale for serial no. 4 should be, 60/20=3. (h of image/h of object).

Mark me brainliest if helped.