Question

someone tells me that ...how many number of oxygen atoms are present in 88g CO2​

Answer 1

Answer:

Moles = Given mass / Atomic mass = Number of atoms / Avagadro number

88 / ( 12 + 32) = Number of atoms / 6.022*10^23

Number of atoms = 6.022*10^23 * 88/ 44

= 12.044 * 10^23

Answer 2

Answer:

Here's your answer

n=?

given mass (m) = 88g

Molar mass (M)= CO2= 12+16×2

= 12+32= 44g

So

$n = \frac{m}{</strong><strong>M</strong><strong>}$

$n = \frac{88}{44} \\ \\ n = 2$

So there are two atoms present in CO2...

Hope it helps ✌