Math, asked by ibbitahir4966, 1 year ago

somu and raju start at the same time from a point. somu walks towards north at a speed of 4 km per hour. raju walks towards east at a speed of 3 km per hour. what is the distance between them after one hour?

Answers

Answered by Puneetrajput085
0
square root if 3 square plus 4 square
5 km
Answered by wifilethbridge
0

Answer:

The distance between them after one hour is 5 km

Step-by-step explanation:

Speed of Somu = 4 km/hr

So, he travels distance in 1 hour = 4 km

Speed of raju= 3 km/hr

So, he travels distance in 1 hour = 3 km

Refer the attached figure

Somu walks towards north at a speed of 4 km per hour

So, distance traveled by Somu in hr = 4 km = AB

Raju walks towards east at a speed of 3 km per hour.

So, distance traveled by Raju in hr = 3 km = AC

So, we are supposed to find BC

So, we will use Pythagoras theorem

Hypotenuse^2= Perpendicular^2+Base^2

BC^2= AB^2+AC^2

BC^2= 4^2+3^2

BC= \sqrt{4^2+3^2}

BC= 5

So,  the distance between them after one hour is 5 km

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