Question

Somu's mother is elder to him by 20 years. After three years square of the age of Somu is 8 more than twice the age of his mother. Find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

let somu's age = x

let the mothers age = x +20

we can form the equation

(x+3)² = 2(x+23) + 8

solving this,

x² + 6x + 9 = 2x + 46 + 8

x² + 6x - 2x = 46 + 8  -9

x² + 4x - 45 = 0

solving the quadratic equation,

x² + 9x - 5x -45 = 0

(x+9)(x-5) = 0

we get values of x as -9 and 5

since age cant be negative

x = 5

Answer 2

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