Question

somya bought two boxes for a total of rupees 4000.sold one box at a profit of 15% and the other box at a loss of 15% if selling price of both boxes is same. find the cost price of each boxes.​

Answer 1

The cost price of 1st box is Rs. 1700

The cost price of second box  is Rs. 2300

Step-by-step explanation:

somya bought two boxes for a total of rupees 4000.

let the CP of 1st box = Rs. x

and the CP of second box = Rs. (4000 - x)...(1)

SP of 1st box = $(\frac{100+profit}{100} \times CP)$

= $\frac{100+15}{100} \times x$

=  $\frac{115}{100} \times x$

S.P of second box =  $(\frac{100-loss}{100} \times CP)$

=  $\frac{100-15}{100} \times (4000-x)$

= $\frac{85}{100} \times (4000-x)$

according to the question

selling price of both boxes is same.

S.P of 1st box = S.P of second box

$\frac{115}{100} \times x$ = $\frac{85}{100} \times (4000-x)$

on solving

23(x) = 17(4000-x)

23x = 68000 - 17x

23x- 17x = 68000

40x = 68000

x = $\frac{68000}{40}$

x = Rs. 1700

Putting the value of  x  in eq (1)

CP of second box = (4000 -x)

= (4000 - 1700)

= Rs. 2300

hence , The cost price of 1st box is Rs. 1700

The cost price of second box  is Rs. 2300

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https://brainly.in/question/13744708

Answer 2

Step-by-step explanation:

Let the cost price of first box be ₹x

Therefore,c.p. of second box will be ₹ (4000-x)

S.P. of first box

P%=15%

S.P.=CP (100+P%/100)

=x(100+15/100)

=x(115/100)

=115/100x

S.P. of second box

L%=15%

S.P.=C.P.(100-L%/100)

=(4000-x)(100-15/100)

=(4000-x)(85/100)

Equating selling price of both boxes

115x/100=(4000-x)(85/100)

115x/100×100/85=4000-x

23/17x+x=4000

(23+17)x/17=4000

40x/17=4000

x=4000 × 17/40

x=1700

cost price of first box is ₹1700

cost price of second box will be 4000-x

=4000-1700

=₹2300

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