Sona can do work 50 days and mona do work 40 days if the work togather mona left work after 10 days how many remaining work sona how manys days
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S = 50
M = 40
total work= LCM of 50, 40= 200
efficiency of ---
S = 4
M = 5
total efficiency = 9
working 10 days according to their efficiency , they complete the work = 10× 9 = 90
again,,
remaining work = 200-90= 110
SONA = remaining work/ efficiency of S
=>110/4 = 55/2 = 27.5 Days will be the answer
M = 40
total work= LCM of 50, 40= 200
efficiency of ---
S = 4
M = 5
total efficiency = 9
working 10 days according to their efficiency , they complete the work = 10× 9 = 90
again,,
remaining work = 200-90= 110
SONA = remaining work/ efficiency of S
=>110/4 = 55/2 = 27.5 Days will be the answer
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