Math, asked by GAkshitha, 3 months ago

Sona deposited ₹ 20000 in a bank for 1year at the rate 10% p.a. Find the amount she

receive at the end of first year from the bank when compounded half-yearly.​

Answers

Answered by goelkavya26
0

Step-by-step explanation:

P=₹20000

R=10% p.a.

T=1 year

A=P(1+r/2×100)¹

20000(1+10/2×100)¹

20000(1+10/200)

20000(200/200+10/200)

20000(210/200)

100×210

₹21000

Therefore the amount received after 1 year is ₹21000

Answered by priyamuralishankar78
0

Answer:

22050 rupees

Step-by-step explanation:

P= 20,000

N= 1 x 2 = 2

R = 10/2 = 5

A= P ( 1 + (R/100) ^ N

= 20,000 ( 1 + 5/100) ^ 2

= 20,000 ( 105/100) ^ 2

= 20,000 ( 21/20) ^ 2

= 20,000 x 21/21 x 21/20

=(20,000 x 441) / 400

= 22050

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