sona is twice as old as Anita. if 6 years is subtracted from Anita's age and four years are added to Sona's age,then sona will be 4 times old as Anita.what are the present ages of Anita and Sona
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let anita age.=x
sona age =2x
a/q =if x-6 and 2x+4
(x-6)=(2x+4)÷4
4(x-6)=2x+4
4x-16=2x+4. (transfer)
4x-2x=4+16
2x=20
x=10
anita =10 years
sona=20years
sona age =2x
a/q =if x-6 and 2x+4
(x-6)=(2x+4)÷4
4(x-6)=2x+4
4x-16=2x+4. (transfer)
4x-2x=4+16
2x=20
x=10
anita =10 years
sona=20years
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