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your answer ... (a)³ - (2√2b³) (a)³ - (√2b)³ we know, a³ - b³ = (a - b)(a² + ab + b²) so, a³ -( √2b)³ = ( a-√2b)(a² + √2²b² + √2ab)
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Answer:
sinS+sin(S-A)+sin(S-B)-sin(S-C)
{sinS-sin(S-C)}+{sin(S-A)+sin(S-B)}
2cos(2S-C)/2sin(C/2)+2sin(C/2)cos(B-A)/2
=2sinC/2[cos(A+B)/2 +cos(B-A)/2]
=2sinC/2 .[2cos(B/2)cos(A/2)]
=4cos(A/2)cos(B/2)sin(C/2)
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