Question

Sonam secured 38% marks in an exam and failed by 10 marks, punam secured 43% marks and got 15 marks more than the minimum required to pass. find maximum marks and pass percentage of marks

Answer 1

Answer:

Step-by-step explanation:

Let the total marks be x.

Sonam got 0.38x and Punam got 0.43x marks.

Pass marks = 0.38x + 10 = 0.43x - 15

When you solve the above equation, you get x = 500.

Pass marks = 0.38(500) + 10 = 200