Question

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9. Find the smallest number which, when divided by 14, 28 and 91, leaves a remainder of 1 in each case.
10. The HCF of two numbers is 16 and their LCM is 96. If one of the numbers is 32, what is the other
number?​

Answer 1

Answer:

9. The smallest number which when divided by 14,28 and 91, leaves a remainder 1 in each case is 365

10.The other number is 48.

Step-by-step explanation:

Answer 2

refer to both the attachment s