Question

Soni has a total of 41 coins of ₹2,₹5 and ₹10. The number of ₹2 coins are lesser than the number of ₹5 coins, which are lesser than the number of ₹10 coins. If she had at least 12 coins of each type, how many ₹2 coins does she have?​

Answer 1

Answer:

answer is 12

Step-by-step explanation:

thanks ........

Answer 2

The answer is, that she has 12 coins of 2 rupees.

Given:

There are a total of 41 coins of rupees 2,5 and 10.

It is also given that rupees 2 coins are less than rupees 5 coins which are lesser than rupees 10 coins and she had at least 12 coins of each type

To Find:

we need to find the number of rupees 2 coins.

Solution:

As there are at least 12 coins of each type the total would be

$12 \times 3 = 36$

The remaining coins are

$= 41 - 36$

$= 5$

There are still 5 coins left.

These coins should be arranged so that number of 10 rupee coins will be more than the 5 rupee coins and 2 rupee coins.

There is only one way to arrange so that this condition is satisfied.

These 5 coins are arranged so that 10 rupee coins will be 15 and 5 rupee coins will be 14 and 2 rupee coins are 12.

The total coins are

$= 15 + 14 + 12$

$= 41$

Therefore, the number of 2 rupee coins is 12.

#SPJ2