Math, asked by abhinavpratapsingh04, 4 days ago

Soni's brother is 8 years older than four-fifth her age. If her brother's age is 32 years, what is Soni's age?​

Answers

Answered by pankaj9234
0

Answer:

54.

Step-by-step explanation:

To find:

Soni's age.

Solution:

Let the Soni's age be x.

Then, age of his brother = 32

A/Q (x × 4/5)+8 = 32

=> (4x + 40)/8 = 32

=> 4x + 40 = 32 × 8

=> 4x + 40= 256

=> 4x = 256 - 40

=> x = 216/4

=> x = 54

Since, Age of Soni = 54

Answered by curi6810
1

Answer:

30

Step-by-step explanation:

According to question

soni brother age=32

soni age =X

x \times  \frac{4}{5}  + 8 = 32 \\  \\  \frac{4x}{5}  = 24 \\  \\ x = 30 \: years

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