Question

Sonia travel 300km to her home party by train and by bus she takes 4 hores if she travels 60 km by train and remaining by bus if she travels 100km by train and remaining by bus she takes 10min longer find the speed of the train and the bus saparatly

Answer 1

Answer:

let the speed of train and bus be u kilometre per hour and v kilometre per hour

Step-by-step explanation:

60/u+240/v=4.....(1)

100/u+200/v=25/6.....(2)

putting 1/u=p and 1/v=q in the equation, we get

=>60p+240q=4.....(3)

=>100p+200q=25/6

=>600p+1200q=...(4)

multiplying equation 3 by 10 we get

=>600p+2400q=40...(5)

subtracting equation 4 from 5 we get 1200 Q =15

=>q=15/200=1/80....(6)

beauty creation 3 we get

=>60p+3=4

=>60p=1

=>p=1/60

=>p=1/u=1/60and q=1/v=1/80

=>u=60&v=80

Answer 2

$\huge\bf\purple{\mid{\fbox{\underline{\underline{Answer}}}}\mid}$

$\bf{https://brainly.in/question/37581179}$

Let the speed of train and bus be u km/h and v km/h respectively.

According to the question,

$\frac{60}{u} + \frac{240}{v} = 4$....(i)

$\frac{100}{u} + \frac{200}{v} = 4 + \frac{10}{60} = \frac{25}{6}$....(ii)

Let $\frac{1}{u} = p\: and \frac{1}{v} = q$

The given equations reduce to:

60p + 240q = 4 ....(iii)

100p + 200q = $\frac{25}{6}$

600p + 1200q = 25....(iv)

Multiplying equation (iii) by 10, we obtain:

600p + 2400q = 40....(v)

Subtracting equation (iv) from equation (v), we obtain:

1200q = 15

q = $\frac{15}{1200} = \frac{1}{80}$

Substituting the value of q in equation (iii), we obtain:

60p + 3 = 4

60p = 1

p = $\frac{1}{60}$

:. p = $\frac{1}{u} = \frac{1}{60}$, q = $\frac{1}{v} = \frac{1}{80}$

u = 60 km/h , v = 80 km/h

Thus, the speed of train and the speed of bus are 60 km/h and 80 km/h respectively.

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️