Question

Sonometre wire is under tension of 10 Newton and the length between the bridges is 2 metre a metre long wire of sonometer has mass of 1 gram reduce the speed of transverse waves and frequency of first harmonic

Answer 1

Answer:

Speed of the transverse wave in the string is 100 m/s and the frequency in first harmonic is 25 Hz

Explanation:

As we know that speed of transverse wave in stretched string is given as

$v = \sqrt{\frac{T}{\mu}}$

so we have

T = 10 N

mass of 1 m long string is 1 g

$v = \sqrt{\frac{10}{10^{-3}}}$

$v = 100 m/s$

now we know that there is 1 loop formation in the string in first harmonic

So we have

$\frac{\lambda}{2} = 2$

$\lambda = 4 m$

now we have frequency

$f = \frac{v}{\lambda}$

$f = \frac{100}{4}$

$f = 25 Hz$

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Topic : Sonometer Experiment

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