Question

Sonu and Monu had adjacent triangular fields with a common boundary of 25 m. The other two sides of Sonu's field were 52 m and 63 m, while Monu's were 114 m and 101 m. If the cost of fertilization is Rs 20 per sq m, then find the total cost of fertilization for both of Sonu and Monu together.

Answer 1

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Sonu and Monu had adjacent triangular fields with a common boundary of 25 m. The other two sides of Sonu's field were 52 m and 63 m, while Monu's were 114 m and 101 m. If the cost of fertilization is Rs 20 per sq m, then find the total cost of fertilization for both of Sonu and Monu together.

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Total Area = 1770 sq m.

Total Area = 1770 sq m.Total Cost of Fertilisation for both of Sonu and Monu together = Rs. 35,400.

Formula Used :-

○ Heron's Formula:-

$\sqrt{s(s - a)(s - b)(s - c)}$

where s is the semiperimeter or half of the triangle's perimeter. Also a, b and c are each of the sides of the triangle.

☆ It is used to find the area of a triangle on the basis of the length of its sides and can be used to find the area of all types of triangles.

EXTRA INFORMATION :-

☆ You can use the formula 1/2×b×h or it is simply half of b times h, when 2 sides of a triangle are given.

☆ The most important thing is that the base and height are at right angles.

Example :-

Height = h = 6

Base = b = 4

Area = ½ bh = ½ × 4 × 6 = 12.