Question

Sonu borrowed a sum of 2000 from a bank for 18 months if the rate is 10% per annum compounds half yearly find compound interest

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Compound\:Interest=315.25\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Principal(p) = 2000 \: rupees \\ \\ \tt: \implies Time(t) = 18 \: months \\ \\ \tt: \implies Rate\%(r) = 10\% \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Compound \: Interest(C.I) = ?$

• According to given question :

$\tt \circ \: Time = \frac{18}{12} = 1 \frac{1}{2} \: year \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies A= p(1 + \frac{ \frac{r}{2} }{100} )^{2t} \\ \\ \tt: \implies A = 2000 \times (1 + \frac{10}{2 \times 100} ) ^{3} \\ \\ \tt: \implies A= 2000 \times (1 + 0.05)^{3} \\ \\ \tt: \implies A = 2000 \times {(1.05)}^{3} \\ \\ \tt: \implies A= 2000 \times 1.157625\\ \\ \green{\tt: \implies A=2315.25\: rupees} \\ \\ \bold{For \: compound \: interest : } \\ \tt: \implies C.I = A - p \\ \\ \tt: \implies C.I = 2315.25 - 2000 \\ \\ \green{ \tt: \implies C.I = 315.25 \: rupees}$

Answer 2

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QUESTION -

Sonu borrowed a sum of 2000 from a bank for 18 months if the rate is 10% per annum compounds half yearly .

Find compound interest.

SOLUTION :

From the above question, we can gather the following information .....

Sonu borrowed a sum of 2000 from a bank for 18 months if the rate is 10% per annum compounds half yearly .

Principle = Rs. 2000

Time = 3 half years.

Rate = 10% per annum = 5 % per half year.

A = 2000 × [ 1 + ( R / 2 ) / 200 ] ^ { 2t )

=> A = 2000 × [ 1.1 ] ^ 3

=> A = 2000 × 1.331

=> A = Rs. 2662 .......... { A 1 }

Compound Interest = A - P

=> C.I = 2000 ( 1.331 - 1 )

=> C.I = 2000 × 0.331 = Rs. 662 ....... { A 2 }