Question

Sonu can do a piece of work in 20 days he started the work and left after some days when 25% work was done after that abhijeet join and completed it working for 10 days in how many days does

Answer 1

Answer:

8

Step-by-step explanation:

Given  

Sonu can do a piece of work in 20 days he started the work and left after some days when 25% work  was done after that abhijeet join and completed it working for 10 days in how many days does

Let the work be 100

Now efficiency of Sonu will be 100 / 20 = 5%

25% of work was done so rest of the work will be 75%

Now efficiency of Abhijeet will be 75/10 = 7.5%

So both efficiency of Sonu and Abhijeet = 7.5 + 5 = 12.5%

Now number of days required by Sonu and Abhijeet to work together = 100 / 12.5 = 8 days

OR

Sonu will do the work in 20 days

3/4  of  the work is done in 10 days by Abhijeet

So 1 work will be in 40 / 3 days

So together they will complete the work in

3/40 + 1/20

= 3 + 2 / 40

= 5/40

= 1/8

= 8 days

Answer 2

Answer:

They have completed the work in 15 days.

Abhijeet can do the complete the work in 13.33 days.

Step-by-step explanation:

Let us assume that the total work is x.

Given that Sonu takes 20 days to complete the work but he left the work when 25% of the work is done.

So, 25% of total work i.e. x/4 work is done by Sonu in 20/4=5 days.

Now the work remaining is (x-x/4)=3x/4.

If Abhijeet join and complete the remaining 3x/4 work in 10 days, then

Abhijeet can do the complete the work x in 10*4/3 = 13.33 days. (Answer)

Again, working together they have completed the work in (5+10)=15 days.

(Answer)