Math, asked by reshmababy269, 1 year ago

Sonu father is four times as old as his son now in twenty years he will be twice as old as his son find their present ages

Answers

Answered by TooFree
20

 \textbf {Hey there, here is the solution.}

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STEP 1: Define their current age:

Let Sonu be x years old

Father = 4x

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STEP 2: Find their age in 20 years time:

Sonu = x + 20

Father = 4x + 20

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STEP 3: Form equation:

In 20 years time, father will be twice as old as his son:

4x + 20 = 2( x + 20)

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STEP 4: Solve x:

4x + 20 = 2( x + 20)

4x + 20 = 2x + 40

2x = 20

x = 10

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STEP 5: Find their current age:

Sonu = x = 10 years old

Father = 4x = 4(10) = 40 years old

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Answer: Sonu is 10 years old and his father 40 years old.

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 \textbf {Cheers}


Answered by anant3375
3

Answer:

yaar vaise sahi answer btaya hai

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