Sonu invested 10% more than mona. Mona invested 10% less than raghu. If the total sum of their investment is rs. 5780, how much amount did raghu invest?
Answers
Answer:
Step-by-step explanation:
Let X amount is invested by raghu;
10 of x is = 0.10x;
Mona invested X-0.1X = 0.9X; (10% less than raghu)
Sonu invested 0.9X- 0.9X (10/100) = 0.81 X (10% less than mona)
Total investment = X+0.9X+0.81X = 5780;
2.71X = 5780;
X = 2132.84 (Invest made by Raghu)
Answer:
Amount invested by Raghu = Rs. 2000
Step-by-step explanation:
Let the amount invested by Raghu = R
Mona (M) Invested 10% less tahn Raghu
∴ Investmenet of mona = M = R - 10% of R
∴ M = R - 0.1R = 0.9R
∴ Investment by Mona (M) = 0.9R ......(1)
Sonu invested 10 % more than mona
∴ Investment by Sonu (S) = M + 10% of M
∴ S = M + 0.1M
.. Subtituting value of M from eqn (1), we get,
S = 0.9R + 0.1×(0.9R)
∴ S = 0.99R
∴ Investment by Sonu (S) = 0.99R ..... (2)
Total investment given = 5780
∴ R + M + S = 5780
Substituting values of M and S from eqn -(1) & (2) ...
∴ R +0.9R + 0.99R = 5780
∴ 2.89R = 5780
∴ R = 5780 ÷ 2.89
∴ R = 2000
∴Amount invested by Raghu = Rs. 2000