Question

Sonu is twice as old as Anu. If six years is subtracted from Anu’s age and four years added to Sonu’s age,then Sonu will be four times Anu’s age. How old were they two years ago ?

Answer 1

Answer:

let anu's age be x

sonu's age=2x

ATQ, 2x+4=4(x-6)

         2x+4=4x-24

         4+24=4x-2x

          28=2x

          x=14

sonu's age=2*14=28

age two years ago:

anu=12 years

sonu=26 years

:)

       

Step-by-step explanation:

Answer 2

Answer:

2 years back, Anu was 12 years old and Sonu was 26 years old.

Step-by-step explanation:

Given :

Sonu = Twice the age of Anu

Six years is subtracted from Anu’s age and four years added to Sonu’s age = Sonu will be four times Anu’s age

To find :

Their ages ages 2 years back

Solution :

Consider present ages as -

• Anu = y
• Sonu = 2y

Six years subtracted from Anu's age = (y - 6)

4 years added to Sonu's age = (2y + 4)

⇒ 4(y - 6) = 2y + 4

⇒ 4y - 24 = 2y + 4

⇒ 4y - 2y = 4 + 24

⇒ 2y = 28

⇒ y = 28/2

⇒ y = 14

Anu's present age = 14 years old

$\rule{300}{1.5}$

★ Sonu's age =

⇒ 2 × y

⇒ 2 × 14

⇒ 28

$\rule{300}{1.5}$

★ Ages 2 years back -

Anu = 14 - 2 = 12 years

Sonu = 28 - 2 = 26 years

$\therefore$ 2 years back, Anu was 12 years old and Sonu was 26 years old.