Question

Sonu's mother age is 25 years more than him .product of their ages before 3 years is 150 find their present age

Answer 1

Answer:

age of son = 8 years

age of mother = 33 years

Step-by-step explanation:

mother's age be x

Sonu age be y

mother is 25 years more than Sonu

x = y + 25

3 years ago age of mother = x - 3

3 years ago age of Sonu = y - 3

3 years ago product of their ages was 150

(x - 3) ( y - 3) = 150

substitute x= y + 25

(y + 25 - 3) (y - 3) = 150

(y + 22)(y-3) = 150

$(y + 22)(y - 3) = 150 \\ {y}^{2} - 3y + 22y - 66 = 150 \\ {y}^{2} + 19y - 66 - 150 = 0 \\ {y}^{2} + 19y - 216 = 0 \\ {y}^{2} + 27y - 8y - 216 = 0 \\ y(y + 27) - 8(y + 27) = 0 \\ (y + 27)(y - 8) = 0 \\ y + 27 = 0 \: \: \: \: y - 8 = 0 \\ y = - 27 \: \: \: \: \: \: \: \: \: y = 8$

as age cannot be in negative, we take the positive value of y = 8

age of son = y = 8

age of mother = x = y + 25 = 8 + 25 = 33

age of mother = 33

hope you get your answer