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2) An object is placed 10cm in front of a concave mirror
of radius of curvature 16cm. The image will be formed at
(a) + 30cm (b)-30cm (0) +40cm col-40cm.
Answers
Answered by
27
Answer :-
v = - 40 cm
Solution :-
For a concave mirror
Object distance ( u ) = - 10 cm
Radius of curvature = - 16 cm
Focal length ( f ) = - 16 / 2 = - 8
Let the image distance be 'v' cm
Using mirror formula
==> 1 / f = 1 / v + 1 / u
==> 1 / ( - 8 ) = 1 / v + 1 / ( - 10 )
==> - 1 / 8 = 1 / v - 1 / 10
==> - 1 / 8 + 1 / 10 = 1 / v
==> ( - 10 + 8 ) / 80 = 1 / v
==> - 2 / 80 = 1 / v
==> v = - 80 / 2
==> v = - 40
Therefore the image will be formed at ( d ) - 40 cm.
Answered by
48
Given that u = 10cm and R= 16cm. So,
f= R/2
f=16/2
=-8 (as the focal length of concave mirror is negative).
Now applying the mirror formula:
1/v + 1/u= 1/f
1/v + 1/(-10) = 1/-8
1/v = 1/-8 + 1/10
1/v = (-10 + 8)/80
1/v = -2 / 80
1/v = -1/40
or v = -40cm
Hence the image will be formed at (-40) cm.
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