Question

Sonya has 4 twenty-dollar bills, 3 ten-dollar bills, 7 five-dollar bills, and 6 one-dollar bills in her
wallet. If she removes one bill from her wallet at random, what is the probability that this one bill
will be enough for her to purchase an $8.50 item?

Answer 1

Answer: Number of favourable outcomes=4+3(twenty and ten are greater than 8.50)=7

Number of total outcomes=20

Probability(enough to purchase an $8.50 item)=(Number of favourable outcomes/(Number of total outcomes)=

7/20

Step-by-step explanation: