sophia took a loan of Rs.80000from a bank. If the rate of interest is 10% per a nnum,find the difference in amounts she would be paying after 1.5 years if the intrest is. i)compound annually ii)compounded half yearly
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Answer:
The difference between the two amounts = Rs.92610−Rs.92400 =Rs.210
Step-by-step explanation:
1) Compounded Annually :
P=Rs.80000
R=10% p.a.
T= 1.5 years ⟹n=1+0.5
Amount for 1st year.
A=P[1+ R/100]^n = Rs.80000[1+ 10/100]=Rs.88000
SI on Rs. 88000 for next 1/2 year
=Rs.88000× 10/100×1/2 = Rs.4400
Therefore, Amount = Rs.88000+Rs.4400 = 92400Rs.
2) Compounded half yearly :
P=Rs.80000
R=10% p.a.= 5% per half year
T= 1.5 years ⟹n = 3
A=Rs.80000[1+ 5/100]^3
A=Rs.92610
Thus, the difference between the two amounts = Rs.92610−Rs.92400 =Rs.210
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