Physics, asked by kennedykhumbo, 9 months ago

soppose 200 J of work is done on a system and 70 calories is extracted from the system as heat. in the sense of the first law of thermodynamics, what are the values of work done, heat and internal change of energy(including algebraic signs)

Answers

Answered by rookee
1

Answer:

Work done is - 200J

Heat is +7 0 calories or +16.6J

Change in internal energy is= -200+16.6=-183. 4J

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