Question

sopve:
A body is released from the top of a building of height 50m. Find the velocity with which the body hits the ground.(g=9.8m/s2)
give with formula and method

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Answer 1

by using the 3rd equation of motion

$2as = {v}^{2} - {u}^{2} \\ 2 \times 98 \div 10 \times 50 = {v}^{2} - {0}^{2} \\ 980 = {v}^{2} \\ v = 31.3 \: metre \: per \: second \: squared$
hence you get your answer as 31.3 m/s sq.


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