Question

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Answer 1

Answer:

$\large\bold\red{(C)-3}$

Step-by-step explanation:

Given,

a parabola $\bold{{y}^{2}=4ax}$

Normal is meeting it at (1,2) and $\bold{({t}^{2},2t)}$

Now,

we know that,

If a normal at $t_{1}$ meets the parabola at $t_{2}$,

Then,

$t_{2}=-t_{1}-\frac{2}{t_{1}}$

Here,

$t_{1}= 1$

and

$t_{2}=t$

Therefore,

we get,

$= > t = - 1 - 2 = - 3$

Hence,

Correct Option is $\bold{(C) -3}$

Answer 2

Answer:

$\huge\tt\purple{(C)−3}$

Step by step explanation:

Given,

a parabola $\bold{{y}^{2}=4ax}$

Normal is meeting it at (1,2) and $\bold{({t}^{2},2t)}$

Now,

we know that,

If a normal at $t_{1}$ meets the parabola at $t_{2,}$

Then,

$t_{2}=-t_{1}-\frac{2}{t_{1}}$

Here,

$t_{1=1}$

and

$t_{2=t}$

Therefore,

we get,

$= > t = - 1 - 2 = - 3$

Hence,

Correct Option is $\bold{(C) -3}$

I hope it helps☺