Question

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Answer 1

Answer:

given:- LHS=tanTeta/(1-cos teta)+cot teta/(1-tan teta)

tan teta/(1-1/tan teta)+(1/tan teta)/(1-tan teta)

tan square teta/(tan teta-1)-1/tan teta(tan teta-1)

(1/tan teta-1)(tan square teta-1/tan teta)

1/(tan teta-1)[(tan cube teta-1)/tan teta]

because we use the identity of a cube -b cube =(a-b)(a square +b square + ab)

[(tan teta-1)( tan square teta +1+tan teta)]

whole divided by tan teta-1×tan teta

tan teta +cot teta+1

sin teta/cos teta+cos teta/sin teta+1

(sin square teta+cos square teta)/sin teta × cos teta +1

1/sin teta × cos teta +1

cosec teta ×sec teta +1=RHS