Question

sorry answer nhi samajh aaya​

Answer 1

Answer:

$let \: the \: 3 \: terms\: A.P \: be \: a - b \: , \: a \: , \: a + d \\ add \: the \: A.P \\ a - d + a + a + d = 33 \\ 3a = 33 \\ a = 11 \\ put \: the \: value \: of \: a \: in \: the \: A.P \\ 11 - d \: , \: 11 \: , \: 11 + d \\ multiply \: the \: A.P \\ (11 - d)(11)(11 + d) = 319 \\ (121 - {d}^{2} )11 = 319 \\ 121 - {d}^{2} = \frac{319}{11} \\ 121 - {d}^{2} = 29 \\ 121 - 29 = {d}^{2} \\ 92 = {d}^{2} \\ d = \sqrt{92} \\ d = 2 \sqrt{23} \\ therefore \: the \: A.P \: should \: be \\ 11 - 2 \sqrt{23} \: , \: 11 \: , \: 11 + 2 \sqrt{23} \\ \\ hope \: it \: helps............ \\ plz \: mark \: as \: brainliest...............$