Question

sorry for it being blur please
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Answer 1

(i) Ar(ABC) =

$\frac{1}{2} \times b \times h$

$= \frac{16 \times 12}{2}$

$= 96 \: {cm}^{2}$

(ii) Ar(ACD) =

$\frac{1}{2} \times b \times h$

$= \frac{29 \times 12}{2}$

$= 174 \: {cm}^{2}$

(iii) Ar(ABCD) = Ar(ABC) + Ar(ACD)

$= 96 + 174$

$= 270 \: {cm}^{2}$

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