Sorry, Solve This. Q.1 Please
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ATQ, if a perpendicular from center which is O is touched on a chord which is AD makes the chord into two equal parts.
AM = MD = AD/2 = 1.5 cm
Join OA and it will become as a radius and its value will be 2cm because diameter is 4cm.
OA = 2 cm
So, in ∆AMO, which is a Right triangle. By Pythagoras theorem,
OA² = AM² + OM²
» OM² = OA² - AM²
» OM² = 2² - 1.5²
» OM² = 4 - 2.25
» OM = √1.75
» OM = 1.3 cm (approx.)
Hence the Length of OM is 1.3 cm.
Regards,
CreativeAB
• The Genius •
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