Sound produced at a point is heard by a person after 5 second,while the same sound is heard by another person after 6 seconds.If the speed of sound is 300 m/s,what could be the maximum and minimum distances between the two persons?
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Answered by
2
5 sec.×300m= 1500m
6 sec.×300m = 1800m
#max. distance = 1500m+1800m=3300m
# min.distance
=1800m-1500m=300m
6 sec.×300m = 1800m
#max. distance = 1500m+1800m=3300m
# min.distance
=1800m-1500m=300m
Answered by
2
s= d/t
d= speed×time.
D1 = 300*5 = 1500 m/sec.
D2 = 300*6 = 1800 m/sec.
Total distance(max) = D1+D2 = 1500+1800 = 3300 m
= 3300/1000 = 3.3 km
(1 m = 1/1000 km).
Min distance = D2-D1 = 1800-1500 = 300m
= 300/1000 = 0.30 km.
So, The max distance taken = 3.3km
& the min distance taken = 0.30 km.
d= speed×time.
D1 = 300*5 = 1500 m/sec.
D2 = 300*6 = 1800 m/sec.
Total distance(max) = D1+D2 = 1500+1800 = 3300 m
= 3300/1000 = 3.3 km
(1 m = 1/1000 km).
Min distance = D2-D1 = 1800-1500 = 300m
= 300/1000 = 0.30 km.
So, The max distance taken = 3.3km
& the min distance taken = 0.30 km.
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