Sound produced by two vibrators have the same wavelength in two different gases to speed of the wave in two gases have 420 metre per second and 400 metre per second the vibrators when sounded together produced 8 beats per second find the frequencies of the two notes and the wavelength
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Answer:
Frequency (f) = 1 /Time (t)
f = 1 /1 = 1
Frequency of gases = 1Hz
Wavelength = velocity / frequency
wavelength = 420 ×1 = 420 lemda
Wavelength of both the gases is same as given that.
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