Question

Sound wave A has period 0.015 s, sound wave B has period 0.025. Which sound has greater frequency ?

Answer 1

Answer:

Explanation:

Hey mate, your answer would be-

we know time period =1/frequency

therefore, frequency=1/time period

=1/0.025Hz

=1000/25Hz (on multiplying both of them by 1000 to remove points and ease it)  

=40 Hz.

Answer 2

Answer:

Wave A has greatest frequency

Explanation:

It is given that,

Time period of sound wave A, $T_A=0.015\ s$

Time period of sound wave B, $T_B=0.025\ s$

The inverse of time period is used to find the frequency of the wave as :

$f=\dfrac{1}{T}$

For wave A,

$f_A=\dfrac{1}{T_A}$

$f_A=\dfrac{1}{0.015\ Hz}$

$f_A=66.66\ Hz$

For wave B,

$f_B=\dfrac{1}{T_B}$

$f_B=\dfrac{1}{0.025\ Hz}$

$f_B=40\ Hz$

It is clear that the frequency of wave A is 66.66 Hz and that of wave B is 40 Hz. So, frequency of wave A is more.