Sound wave moving at 340ms-¹ in air approaches a pool of water in which its wavelength is four times that of the wavelength in air. What will be the speed of the wave in water?
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Answer:85 ms-¹
Explanation:
x1 speed in air
x2 speed in water
y1 wavelength in air
y2 wavelength in water
=y/4y=x2/340
=x2=340/4
=85
x1/x2=y2/y1
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