Question

sound waves of frequency 400hz of speed 320 m/s. Phase difference between points 0.2m apart?

Answer 1

Explanation:

Let,

Frequency of wave is, f=400Hz

Velocity of wave is, v=320ms

−1

The phase difference is, ϕ=90

∘

=

2

π

The wavelength of wave is, λ

λ=

f

v

λ=

400

320

λ=0.8m

Now, the phase difference between two particles in a wave is

2π

ϕ

=

λ

x

where, x is the distance between two particles in a wave.

x=

2π

λϕ

x=

2π

0.8(

2

π

)

x=

4

0.8

=0.2m

x=20cm

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Answer 2

Answer:

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