Question

Sound waves of frequency 660 hz fall normally on a perfectly reflecting wall the shortest distance from wall at which the air particle has maximum amplitude of vibration

Answer 1

The shortest distance from wall at which the air particle has maximum amplitude of vibration is given by 0.25m

Explanation :

Given ,

frequency of sound, f = 660 Hz

we know that velocity of sound, v = 330 m/s

Hence the wavelength of sound can be calculated as ,

λ = v/f = 330/660 = 0.5 m

we know that maximum amplitude occurs at λ/2 = 0.5/2 = 0.25m

hence, the shortest distance from wall at which the air particle has maximum amplitude of vibration is given by 0.25m

Answer 2

Answer:

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