Sound with intensity larger than 120 dB appears painful to a person. A small speaker delivers 2.0 W of audio output. How close can the person get to the speaker without hurting his ears?
Answers
Answer ⇒ 40 cm.
Explanation ⇒
The intensity of the sound at a distance r from the speaker,
I = 2.0/4πr²
I = 1/2πr²
Since,
Sound level = 10 log [I/I₀]
∴ 120 = 10 log [(1/2πr²)/10⁻¹²]
Since, I₀ = 10⁻¹² W/m², thus,
Thus, log [10¹²/2πr²] = 12
log 10¹² -log [2πr²] = 12
12 - log[2π] - log r² = 12
log r² = -log [2π] = log [2π]⁻¹
r² = [2π]⁻¹
r² = 1/2π
r² = 0.16
r = 0.40 m
or r = 40 cm
Hope it helps.
Answer:
The intensity of the sound at a distance r from the speaker,
I = 2.0/4πr²
I = 1/2πr²
Since,
Sound level = 10 log [I/I₀]
∴ 120 = 10 log [(1/2πr²)/10⁻¹²]
Since, I₀ = 10⁻¹² W/m², thus,
Thus, log [10¹²/2πr²] = 12
log 10¹² -log [2πr²] = 12
12 - log[2π] - log r² = 12
log r² = -log [2π] = log [2π]⁻¹
r² = [2π]⁻¹
r² = 1/2π
r² = 0.16
r = 0.40 m
or r = 40 cm
Explanation: