Math, asked by raoamitesh009, 1 month ago

Sourabhi invested an amount of Rs 16,840 at the rate of 6 p.c.p.a. for 5 years. What total amount will she
obtain with the simple interest at the said rate at the end of 5 years?​

Answers

Answered by EnchantedGirl
11

Given:-

  • Principle = 16840
  • Rate = 6
  • Time = 5years

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To find:-

  • Total amount with which she  will obtain with the simple interest at the said rate at the end of 5 years?​

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Solution:-

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We know:

\leadsto \underline{\boxed{\sf S.I=\frac{PRT}{100} }}

Putting the values,

:\implies \sf S.I = \dfrac{16840 \times 5\times 6}{100} \\\\:\implies \underline{\sf S.I = 5052}\\\\

Hence,

The simple intrest is Rs.5052

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Using the formula,

\leadsto \underline{\boxed{\sf Amount = Principle+S.I}}

Putting values,

\sf Total\ amount\ received :-\\\\:\implies \sf A = 16840 +5052\\\\:\implies \underline{\boxed{\sf A = 21892}}\\\\

Hence,

The total amount  she  obtains with the simple interest at the said rate at the end of 5 years is Rs.21892.

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Know more:-

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Simple interest on yearly basis:

Simple Interest for n months,

  • (P × n × R)/ (12 ×100)

Compound interest:-

  • A = P (1 + r/n)⁽ⁿᵗ⁾

Where,

A = final amount

P=initial principal balance

r=interest rate

n=number of times interest applied per time period

t=number of time periods elapsed

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Answered by cool1403
5

Answer :-

\large\leadsto\mathsf{Given:}

Principle = Rs.16,840

Rate = 6%

Time = 5years

\large\leadsto\mathsf{To\: find:}

Amount at the end of 5 years

\large\leadsto\mathsf{Solution:}

\purple{\boxed{\sf{SI =  \frac{P \times R \times T}{100} }}}

\large\mathsf{SI =  \frac{16840 \times 6 \times 5}{100} }

\pink{\boxed{\sf{SI=Rs.5052}}}

\orange{\boxed{\sf{Amount=SI+Principle}}}

Amount = 16840+5052

\large\red{\boxed{\sf{Amount=Rs.12,892}}}

Hope it helps..

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