Math, asked by devapriya6658, 6 months ago

sourav's age three times of his son age.eight years ago he was four times his son age. find their present age
please step by step explanation​

Answers

Answered by Anonymous
2

Answer:

So Son's age=24 yrs and

Saurav's age=24*3=72 yrs

Step-by-step explanation:

Let the present age of son is x

then Saurav's age=3x

8 yrs ago their ages were

Son: x-8

saurav : 3x-8

as per given

3x-8=4(x-8)

3x-8=4x-32

or 4x-32=3x-8

4x-3x=32-8

x=24

So Son's age=24 yrs and

Saurav's age=24*3=72 yrs

Answered by EliteZeal
25

\huge{\blue{\bold{\underline{\underline{Answer :}}}}}

 \:\:

 \large{\green{\underline \bold{\tt{Given :-}}}}

 \:\:

  • Sourav's age is three times of his son's age

 \:\:

  • Eight years ago he was four times his son age

 \:\:

 \large{\red{\underline \bold{\tt{To \: Find :-}}}}

 \:\:

  • Their present ages

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

  • Let the present age of Saurav be "x"

  • Let the present age of his son be "y"

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

Sourav's age is three times of his son's age

 \:\:

➠ x = 3y ------- (1)

 \:\:

 \underline{\bold{\texttt{Saurav's age 8 years ago :}}}

 \:\:

➠ x - 8

 \:\:

 \underline{\bold{\texttt{Son's age 8 years ago :}}}

 \:\:

➠ y - 8

 \:\:

Also given that eight years ago Saurav was four times his son age

 \:\:

So,

 \:\:

➜ x - 8 = 4(y - 8)

 \:\:

➜ x - 8 = 4y - 32

 \:\:

➜ x - 4y = - 32 + 8

 \:\:

➜ x - 4y = -24 ------ (2)

 \:\:

Putting x = 3y from (1) to (2)

 \:\:

➜ x - 4y = -24

 \:\:

➜ 3y - 4y = -24

 \:\:

➜ -y = -24

 \:\:

➨ y = 24 -------- (3)

 \:\:

  • Hence his son's present age is 24 years

 \:\:

Putting y = 24 from (3) to (1)

 \:\:

➜ x = 3y

 \:\:

➜ x = 3(24)

 \:\:

➨ x = 72

 \:\:

  • Hence present age of Saurav is 72 years

 \:\:

∴ The present ages of Saurav and his son are 72 years & 24 years respectively

 \:\:

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