sourav's age three times of his son age.eight years ago he was four times his son age. find their present age
please step by step explanation
Answers
Answer:
So Son's age=24 yrs and
Saurav's age=24*3=72 yrs
Step-by-step explanation:
Let the present age of son is x
then Saurav's age=3x
8 yrs ago their ages were
Son: x-8
saurav : 3x-8
as per given
3x-8=4(x-8)
3x-8=4x-32
or 4x-32=3x-8
4x-3x=32-8
x=24
So Son's age=24 yrs and
Saurav's age=24*3=72 yrs
- Sourav's age is three times of his son's age
- Eight years ago he was four times his son age
- Their present ages
- Let the present age of Saurav be "x"
- Let the present age of his son be "y"
Sourav's age is three times of his son's age
➠ x = 3y ------- (1)
➠ x - 8
➠ y - 8
Also given that eight years ago Saurav was four times his son age
So,
➜ x - 8 = 4(y - 8)
➜ x - 8 = 4y - 32
➜ x - 4y = - 32 + 8
➜ x - 4y = -24 ------ (2)
⟮ Putting x = 3y from (1) to (2) ⟯
➜ x - 4y = -24
➜ 3y - 4y = -24
➜ -y = -24
➨ y = 24 -------- (3)
- Hence his son's present age is 24 years
⟮ Putting y = 24 from (3) to (1) ⟯
➜ x = 3y
➜ x = 3(24)
➨ x = 72
- Hence present age of Saurav is 72 years
∴ The present ages of Saurav and his son are 72 years & 24 years respectively
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