Sove it pls i m not getting how to solve this the ques is 8n the picture attached
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Given: The ten's place of two digit number is two more than ones place.
Let ten's digit be x then ones as y.
→ x = y + 2
Given: Square of ten's digit exceeds ones digit by 9 times.
→ x² = 9y
→ (y + 2)² = 9y
→ y² + 4 + 4y = 9y
→ y² - 5y + 4 = 0
→ y² - 4y - y + 4 = 0
→ y(y - 4) - 1(y - 4) = 0
→ (y - 4)(y - 1) = 0
→ y = 4 and 1
Hence, x = 2 + 4 and x = 2 + 1
→ x = 6 and 3.
Thus, either number is 64 or 31.
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