Question

Sove the following equation by transposition method:-​

Answer 1

Solve :-

$\tt \:  \dfrac{3m - 1}{3} - \dfrac{2m + 2}{6} = 5$

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Step by Step explanation:-

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$\tt \:  \longrightarrow \: \dfrac{3m - 1}{3} - \dfrac{2m + 2}{6} = 5$

$\tt \:  \longrightarrow \:\dfrac{2(3m - 1) - (2m + 2)}{6} = 5$

$\tt \:  \longrightarrow \:\dfrac{6m - 2 - 2m - 2}{6} = 5$

$\tt \:  \longrightarrow \:\dfrac{4m - 4}{6} = 5$

$\tt \:  \longrightarrow \:4m - 4 = 30$

$\tt \:  \longrightarrow \:4m = 34$

$\tt\implies \:m = \dfrac{17}{2}$

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Verification

Verification Consider LHS

$\tt \:  \dfrac{3m - 1}{3} - \dfrac{2m + 2}{6}$

☆ On substituting the value of m, we get

$\tt \:  \longrightarrow \: \dfrac{3 \times \dfrac{17}{2} - 1}{3} - \dfrac{2 \times \dfrac{17}{2} + 2}{6}$

$\tt \:  \longrightarrow \:\dfrac{51 - 2}{6} - \dfrac{17 + 2}{6}$

$\tt \:  \longrightarrow \:\dfrac{49}{6} - \dfrac{19}{6}$

$\tt \:  \longrightarrow \:\dfrac{49 - 19}{6}$

$\tt \:  \longrightarrow \:\dfrac{30}{6}$

$\tt \:  \longrightarrow \:5$

$\tt\implies LHS = RHS$

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$\bf\implies \:Hence, Verified$

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