Question

sove the linear equation 2x+3y=1​

Answer 1

Let us Solve the equations 2x−3y=1 and x+2y=−3 by the method of elimination

2x−3y=1      ......(1)

x+2y=−3      ......(2)

Multiply eqn(1) by 1 and eqn(2) by 2

2x−3y=1      ......(3)

2x+4y=−6      ......(4)

Equation (3)−(4)

2x−3y−2x−4y=1−(−6)

⇒−7y=1+6=7

∴y=−77=−1

Substituting the value of y=−1 in eqn(1) we get

2x−3×−1=1

or 2x+3=1 or 2x=1−3=−2 or x=2−2=−1

Hence the co-ordinates are (−1,−1) lies in third quadrant.