sove this its urgent pls
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boht hard question
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Percentage of oxygen=27.6Precentage of metal=100-27.6=72.4Formula of the metal oxide=M3O4Let the atomic mass of the metal= xPercentage by weight of the metal in the oide M3O4=3x *100/3x+64=72.43x=0.724*3x+0.724*640.828x=46.336x=56The atomic mass of the metal=56 Element Precentage Atomic Mass Atomic ratio Simplest ratio whole no.ratioM 70 56 70/56=1.25 1.25/1.25=1 2O 30 16 30/16 1.88/1.25=1.5 3 M2O3
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